How do you find the six trigonometric functions of $(19pi)/3$ degrees?

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Answer 1 · 2018-03-17T05:23:35

As below.

To find the six trigonometric functions of $(19pi)/3$

We can write $(19pi)/3$ as $(19pi)/3 - 6pi = (19pi - 18pi)/3 = pi/3$

Angle $pi/3$ is in first quadrant where all the six trigonometric fiunctions are positive.

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$sin (pi/3) = sin 60 = sqrt3/2$

$csc (pi/3) = csc 60 = = 1/ sin(pi/3) = 2/sqrt3$

$cos (pi/3) = cos 60 = 1/2$

$sec (pi/3) = sec 60 = 1/cos (pi/3) = 2$

$tan (pi/3) = tan 60 = sqrt3$

$cot (pi/3) = cot 60 = 1/sqrt3$

How do you find the six trigonometric functions of (19pi)/3(19pi)/3 degrees?