How do you find the six trigonometric functions of $(13pi)/4$ ?

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Answer 1 · 2015-06-15T18:07:53

Six trig functions of $(13pi)/4$

On the trig unit circle,

$sin ((13pi)/4) = sin (5pi/4 + 2pi)$ = $- sin (pi/4) = (-sqrt2)/2$
$cos ((13pi)/4) = cos (5pi/4 + 2pi) = -cos (pi/4) = (-sqrt2)/2$

$tan ((13pi)/4) = 1$

$cot ((13pi)/4) = 1$

$sec ((13pi)/4) = -sqrt2$

$csc ((13pi)/4) = -sqrt2$

How do you find the six trigonometric functions of (13pi)/4(13pi)/4?