How do you fInd the sine, cosine, and tangent of $(11pi)/4$ radians?

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Answer 1 · 2018-07-12T20:25:39

$1/\sqrt2,\ -1/\sqrt2 \ \ &\ \ -1$

$\sin({11\pi}/4)=\sin(2\pi+{3\pi}/4)=\sin({3\pi}/4)=\sin(\pi-{\pi}/4)=\sin(\pi/4)=1/\sqrt2$

$\cos({11\pi}/4)=\cos(2\pi+{3\pi}/4)=\cos({3\pi}/4)=\cos(\pi-{\pi}/4)=-\cos(\pi/4)=-1/\sqrt2$

$\tan({11\pi}/4)=\tan(2\pi+{3\pi}/4)=\tan({3\pi}/4)=\sin(\pi-{\pi}/4)=-\tan(\pi/4)=-1$

How do you fInd the sine, cosine, and tangent of (11pi)/4(11pi)/4 radians?