How do you find the roots of #12x=9x^2+4# by factoring?

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Answer 1 · 2016-10-22T02:16:08

#x=2/3#

#12x=9x^2+4#

Subtract #12x# from both sides.

#0=9x^2-12x+4# or #9x^2-12x+4=0#

Factorise the equation.

#9x^2-6x-6x+4=0#

#3x(3x-2)-2(3x-2)=0#

#(3x-2)(3x-2)=0#

#3x-2=0#

#:.x=2/3#