How do you find the rest of the zeros given one of the zero #c=1/2# and the function #f(x)=2x^3-3x^2-11x+6#?
1 Answer
Feb 15, 2017
-2 and 3
Explanation:
Now divide the polynomial by
Quotient is now
or,
The rest of the zeros are therefor x= -2 and x=3