How do you find the remainder when #x^3+8x^2+11x-20# is divided by x-5?

1 Answer
Shwetank Mauria
Sep 17, 2016

When #x^3+8x^2+11x-20# is divided by #(x-5)#, the remainder is #360#

Explanation:

According remainder theorem, if a polynomial #f(x)# is divided by a binomial of degree #1# i.e. #(x-a)#, the remainder is #f(a)#.

Hence, when #x^3+8x^2+11x-20# is divided by #(x-5)#, the remainder is

#f(5)=5^3+8xx5^2+11xx5-20#

= #125+8xx25+55-20#

= #125+200+55-20#

= #360#

Related questions
See all questions in Remainder and Factor Theorems
Impact of this question
2237 views around the world
You can reuse this answer
Creative Commons License