How do you find the remainder when $x^3+7x^2+2x-40$ is divided by x-5?

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Answer 1 · 2016-11-22T20:57:56

The remainder is $=270$

Use the remainder theorem

Let $f(x)=x^3+7x^2+2x-40$

Then we calculate $f(5)$

$f(5)=5^3+7*5^2+2*5-40$

$=125+175+10-40=270$

So the remainder is $270$

How do you find the remainder when x^3+7x^2+2x-40x^3+7x^2+2x-40 is divided by x-5?