How do you find the real solutions of the polynomial #9x^2+5x^3=6x^4#?

1 Answer
Jim G.
Jun 10, 2017

#x=0,x~~-0.88,x~~1.71#

Explanation:

#"rearrange the polynomial, equating to zero"#

#rArr6x^4-5x^3-9x^2=0#

#rArrx^2(6x^2-5x-9)=0larr" common factor"#

#"factor " 6x^2-5x-9" using the "color(blue)"quadratic formula"#

#"with " a=6,b=-5" and " c=-9#

#x=(5+-sqrt(25+216))/12=(5+-sqrt241)/12#

#rArrx~~1.71" or " x~~-0.88 " or x=0 #

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