How do you find the range of $y = t^2 + t - 2$ ; given Domain = {-2, -1, 0, 1}?

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Answer 1 · 2016-07-07T04:48:42

The accompanying range is given by the y coordinates of the points within the domain.

Substituting:

$(-2)^2 - 2 - 2 = 0$

$(-1)^2 - 1 - 2 = -2$

$0^2 - 0 - 2 = -2$

$(1)^2 - 1 - 2 = -2$

Hence, the range is ${0, -2, -2, -2}$ , or ${y| 0, -2, -2, -2}$ .

Hopefully this helps!

How do you find the range of y = t^2 + t - 2y = t^2 + t - 2; given Domain = {-2, -1, 0, 1}?