How do you find the range of $y = 3x + 10$ ?

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Answer 1 · 2015-09-20T13:21:13

The range of this function is the whole of $RR$ since for any value of $y$ there is a value of $x$ such that $y = 3x+10$

We can solve for $x$ in terms of $y$ as follows:

Subtract $10$ from both sides to get:

$y - 10 = 3x$

Divide both sides by $3$ to get:

$x = (y - 10)/3$

The right hand side is defined for any $y in RR$ , so we can always find an $x$ that yields a given value of $y$ .

How do you find the range of y = 3x + 10y = 3x + 10?