How do you find the range of $x^3 - 5$ given D = {0, 1, 2, 3, 4}?

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Answer 1 · 2017-07-11T15:52:30

Im $f = {f(0), f(1), f(2), f(3), f(4)}$

$f(0) = 0^3 - 5 = -5$
$f(1) = 1^3 - 5 = -4$
$f(2) = 2^3 - 5 = 3$
$f(3) = 3^3 - 5 = 22$
$f(4) = 4^3 - 5 = 59$

${-5,-4,3,22,59}$

How do you find the range of x^3 - 5 x^3 - 5 given D = {0, 1, 2, 3, 4}?