How do you find the range of the function #y=2x^2+1# when the domain is {9, 3, 99}?

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Answer 1 · 2015-06-19T14:52:43

This function has a range between #19# an #19603#

The domain of the function has only 3 elements, so it will be easy just to calculate the values:

#f(3)=2*3^2+1=2*9+1=18+1=19#
#f(9)=2*9^2+1=2*81+1=162+1=163#
#f(99)=2*99^2+1=2*9801+1=19602+1=19603#

So the function has only the values from range: #<19;19603>#

Answer 2 · 2015-06-19T16:35:01

For a function with finite domain, evaluate the function at each value. The set of results is the range.

The range of a function is the set of all values the function attains (the set of 'y-values' or of 'outputs')

For the function given, we find:
#f (9)=163#
#f (3)=19#
#f (99)=19 603#
So the range is #{163, 19, 19603}#,