How do you find the range of $h(x) = x/2$ if {-2, -2, 0, 1/2}?

Question

1340 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-11-25T23:09:58

See a solution process below:

Substitute each value in the Domain for $color(red)(x)$ and calculate $h(x)$ to find the Range of the function:

For $x = -2$ :

$h(color(red)(x)) = color(red)(x)/2$ becomes:

$h(color(red)(-2)) = color(red)(-2)/2$

$h(color(red)(-2)) = -1$

For $x = -2 ("Again?")$ :

$h(color(red)(x)) = color(red)(x)/2$ becomes:

$h(color(red)(-2)) = color(red)(-2)/2$

$h(color(red)(-2)) = -1$

For $x = 0$ :

$h(color(red)(x)) = color(red)(x)/2$ becomes:

$h(color(red)(0)) = color(red)(0)/2$

$h(color(red)(-2)) = 0$

For $x = 1/2$ :

$h(color(red)(x)) = color(red)(x)/2$ becomes:

$h(color(red)(0)) = color(red)(1/2)/2$

$h(color(red)(-2)) = 1/4$

The Range of the function is: ${-1, 0, 1/4}$

How do you find the range of h(x) = x/2h(x) = x/2 if {-2, -2, 0, 1/2}?