How do you find the range of #f(x)=x^2-x-2#? Algebra Expressions, Equations, and Functions Domain and Range of a Function 1 Answer Konstantinos Michailidis Sep 18, 2015 The range is #[-9/4,+oo)# Explanation: The domain is #R# and we have that #y=(x^2-x+1/4)-2-1/4=>y=(x-1/2)^2-9/4=>y+9/4=(x-1/2)^2=> y+9/4>=0=>y>=-9/4# Answer link Related questions How do you determine if (-1, 4), (2, 8), (-1, 5) is a function? What is the domain for #f(x)=2x-4#? What is the domain and range for (3,1), (1,-4), and (2, 8)? What is the domain and range of a linear function? Is domain the independent or dependent variable? How do you find the domain and range of a function in interval notation? How do you find domain and range of a rational function? How do you find domain and range of a quadratic function? How do you determine the domain and range of a function? What is Domain and Range of a Function? See all questions in Domain and Range of a Function Impact of this question 1155 views around the world You can reuse this answer Creative Commons License