How do you find the range of $f(x)=x^2-x-2$ ?

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Answer 1 · 2015-06-28T22:53:20

Range 0f f(x) = x^2 - x - 2

x of vertex -> x = -b/2a = 1/2
y of vertex -> f(1/2) = 1/4 - 1/2 - 2 = -9/4

The graph of f(x) is a parabola that opens upward (a > 0) and with Minimum (1/2, -9/4).
Range of f(x) -> (+infinity, -9/4) and (-9/4, +infinity)

How do you find the range of f(x)=x^2-x-2f(x)=x^2-x-2?