How do you find the range of f(x)= -6(x+4)^2-12?
1 Answer
Jun 7, 2018
Explanation:
"we require to find the vertex and if max/min"
"the equation of a parabola in "color(blue)"vertex form" is.
color(red)(bar(ul(|color(white)(2/2)color(black)(y=a(x-h)^2+b)color(white)(2/2)|)))
"where "(h,k)" are the coordinates of the vertex and a"
"is a multiplier"
y=-6(x+4)^2-12" is in vertex form"
"with vertex "=(-4,-12)
"to determine if vertex is max/min"
• " if "a>0" then minimum "uuu
• " if "a<0" then maximum "nnn
"here "a=-6" hence maximum at "(-4,-12)
"range is "(-oo,-12]
graph{-6(x+4)^2-12 [-40, 40, -20, 20]}
