How do you find the range of $f(x)= 2/(3x-1)$ ?

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Answer 1 · 2018-03-21T16:34:10

The range is $RR -{0}$

The function is

$f(x)=2/(3x-1)$

To find the range, proceed as follows

Let $y=2/(3x-1)$

Therefore,

$y(3x-1)=2$

$y3x-y=2$

$3xy=(2+y)$

$x=(y+2)/(3y)$

Therefore,

As the denominator is $!=0$

$y!=0$

The range is $RR -{0}$

graph{2/(3x-1) [-10, 10, -5, 5]}

How do you find the range of f(x)= 2/(3x-1)f(x)= 2/(3x-1)?