How do you find the range of f(x)=1/(x-3)?
1 Answer
Jun 18, 2018
Explanation:
"let "y=1/(x-3)
"rearrange making "x" the subject"
y(x-3)=1
xy-3y=1
x=(1+3y)/y
"the denominator "!=0
"range "y in(-oo,0)uu(0,oo)
graph{1/(x-3) [-10, 10, -5, 5]}
