How do you find the range and interquartile range for 37, 19, 13, 11, 10?

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Answer 1 · 2017-01-20T07:29:17

Range is #27# and interquartile range is #17 1/2#.

Let us first arrange them in increasing order and data appears as

#10,11,13,19,37#

As the range is difference between maximum and nimimum

Range is #37-10=27#

Median is the value of #((n+1)/2)^(th)# term i.e. #(5+1)/2=3^(rd)# term i.e. #13#

First quartile #Q_1# is #((n+1)/4)^(th)=(1 1/2)^(th)# term and third quartile #Q_3# is #3((n+1)/4)^(th)=(4 1/2)^(th)# term.

Hence, we can take #Q_1# as #(10+11)/2=10 1/2# and #Q_3# as #(19+37)/2=28#.

As interquartile range is #Q_3-Q_1#, it is #28-10 1/2=17 1/2#