How do you find the quadratic function with vertex (-1/4, 3/2) and point (-2,0)?
1 Answer
May 27, 2018
Explanation:
#"the equation of a parabola in "color(blue)"vertex form"# is.
#color(red)(bar(ul(|color(white)(2/2)color(black)(y=a(x-h)^2+k)color(white)(2/2)|)))#
#"where "(h,k)" are the coordinates of the vertex and a"#
#"is a multiplier"#
#"here "(h,k)=(-1/4,3/2)#
#y=a(x+1/4)^2+3/2#
#"to find a substitute "(-2,0)" into the equation"#
#0=a(-7/4)^2+3/2=49/16a+3/2#
#a=-3/2xx16/49=-24/49#
#y=-24/49(x+1/4)^2+3/2larrcolor(red)"in vertex form"#
