How do you find the product #(x-5y)^2#?

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Answer 1 · 2017-07-26T02:49:25

#(x-5y)^2=x^2-10xy+25y^2#

Given:

#(x-5y)^2#

Since the binomial is squared, multiply the binomial by itself using the FOIL method.

#(x-5y)(x-5y)#

![http://www.mathcaptain.com/algebra/http://foil-method.html](https://useruploads.socratic.org/nmRvm381QHmDo9NUX71P_foil-method.JPG)

#x^2-5xy-5xy+25y^2#

Simplify.

#x^2-10xy+25y^2#