How do you find the product #[(t^2+3t-8)-(t^2-2t+6)](t-4)#?

1 Answer
Anjali G · Sonnhard
Jun 6, 2018

#[(t^2+3t-8)-(t^2-2t+6)] (t-4) = 5t^2-34t+56#

Explanation:

# [(cancel(t^2)+3t-8)-(cancel(t^2)-2t+6)] (t-4)#

# = (5t-14)(t-4)#

We have the first term:
#t^2+3t-8-t^2+2t+6=5t-14#
so we get
# [(cancel(t^2)+3t-8)-(cancel(t^2)-2t+6)] (t-4)#

# = (5t-14)(t-4)#

#(5t-14)(t-4)=5t^2-14t-20t+56#
Combining like terms, we get:
#5t^2-34t+56#

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