How do you find the product of #(n-5)(n+1)#?

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Answer 1 · 2018-05-02T21:29:23

#n^2 -4n -5#

=#(n-5)(n+1)#
=#[n(n+1) -5(n+1)]#
=#n^2 +n -5n -5#
=#n^2 -4n -5#

HAPPY LEARNING!!

Answer 2 · 2018-05-02T21:34:51

#n^2-4n-5#

Use the FOIL method: First Outer Inner Last

So you have

#n^2+n-5n-5#

Simplify

#n^2-4n-5#