How do you find the product of #(b+3)(b+4)#?

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Answer 1 · 2017-03-07T23:28:20

See the entire solution process below:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(b) + color(red)(3))(color(blue)(b) + color(blue)(4))# becomes:

#(color(red)(b) xx color(blue)(b)) + (color(red)(b) xx color(blue)(4)) + (color(red)(3) xx color(blue)(b)) + (color(red)(3) xx color(blue)(4))#

#b^2 + 4b + 3b + 12#

We can now combine like terms:

#b^2 + (4 + 3)b + 12#

#b^2 + 7b + 12#