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How do you find the product of #(4c+1)(2c+1)#?

1 Answer

Sep 7, 2016

#8 c^(2) + 6 c + 1#

Explanation:

We have: #(4 c + 1) (2 c + 1)#

Let's expand the parentheses:

#= (4 c) (2 c) + (4 c) (1) + (1) (2 c) + (1) (1)#

#= 8 c^(2) + 4 c + 2 c + 1#

#= 8 c^(2) + 6 c + 1#

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