How do you find the product #(8d+3)(5d+2)#?

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Answer 1 · 2017-02-17T22:18:00

See the entire solution process below:

To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(8d) + color(red)(3))(color(blue)(5d) + color(blue)(2))# becomes:

#(color(red)(8d) xx color(blue)(5d)) + (color(red)(8d) xx color(blue)(2)) + (color(red)(3) xx color(blue)(5d)) + (color(red)(3) xx color(blue)(2))#

#40d^2 + 16d + 15d + 6#

We can now combine like terms:

#40d^2 + (16 + 15)d + 6#

#40d^2 + 31d + 6#