How do you find the product $(5 r^{3}) (4 r^{4})$ $(5r^3)(4r^4)$ ?

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How do you find the product $(5 r^{3}) (4 r^{4})$ $(5r^3)(4r^4)$ ?

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Answer 1 · 2018-07-30T18:15:26

$20 r^{7}$ $20r^7$

Explanation:

$using the law of exponents$ $"using the "color(blue)"law of exponents"$

$∙ x a^{m} \times a^{n} = a^{(m + n)}$ $•color(white)(x)a^mxxa^n=a^((m+n))$

$5 r^{3} \times 4 r^{4}$ $5r^3xx4r^4$

$= (5 \times 4) \times r^{(3 + 4)} = 20 r^{7}$ $=(5xx4)xxr^((3+4))=20r^7$

Answer 2 · 2018-07-30T19:14:58

$20 r^{7}$ $20r^7$

Explanation:

We can rewrite this as

$5 \cdot 4 \cdot r^{3} \cdot r^{4}$ $5*4*r^3*r^4$

This simplifies to

$20 \cdot r^{3} \cdot r^{4}$ $20*color(blue)(r^3*r^4)$

When we have the same base ( $r$ $r$ ), we can just add the exponents. This simplifies to

$20 r^{7}$ $20color(blue)(r^7)$

Hope this helps!

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How do you find the product $(5 r^{3}) (4 r^{4})$ $(5r^3)(4r^4)$ ?

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