How do you find the product #(2n+3)(n+9)#?

1 Answer
Jim G.
Apr 26, 2017

#2n^2+21n+27#

Explanation:

Each term in the second bracket is multiplied by each term in the first bracket as shown below.

#(color(red)(2n+3))(n+9)#

#=color(red)(2n)(n+9)color(red)(+3)(n+9)#

#=(color(red)(2n)xxn)+(color(red)(2n)xx9)+(color(red)(3)xxn)+(color(red)(3)xx9)#

#=2n^2+18n+3n+27#

#=2n^2+21n+27#

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