How do you find the power series for f(x)=(2x)/(1+x^4) and determine its radius of convergence?

1 Answer
Oct 17, 2017

(2x)/(1+x^4) = 2sum_(n=0)^oo(-1)^nx^(4n+1)

for absx < 1

Explanation:

Start from the geometric series:

sum_(n=0)^oo q^n = 1/(1-q)

which converges for absq < 1.

Substituting q=-x^4 we have:

1/(1+x^4) = sum_(n=0)^oo (-x^4)^n = sum_(n=0)^oo (-1)^nx^(4n)

converging for absx^4 < 1, that is for abs x < 1.

Multiplying by 2x term by term we finally get:

(2x)/(1+x^4) = 2sum_(n=0)^oo(-1)^nx^(4n+1)