How do you find the missing coordinate if the 1st coordinate is C (6,5) has midpoint M (4,2)?

1 Answer
Aug 13, 2017

See a solution process below:

Explanation:

The formula to find the mid-point of a line segment give the two end points is:

(x_M, y_M) = ((color(red)(x_1) + color(blue)(x_2))/2 , (color(red)(y_1) + color(blue)(y_2))/2)

Where (x_M, y_M) is the midpoint and the given points are:

(color(red)(x_1), color(red)(y_1)) and (color(blue)(x_2), color(blue)(y_2))

First, find the x value of the missing coordinate:

Substituting the information from the problem gives:

4 = (color(red)(6) + color(blue)(x_2))/2

We can now solve for color(blue)(x_2):

color(green)(2) xx 4 = color(green)(2)((color(red)(6) + color(blue)(x_2))/2)

8 = cancel(color(green)(2))((color(red)(6) + color(blue)(x_2))/color(green)(cancel(color(black)(2))))

8 = color(red)(6) + color(blue)(x_2)

-color(green)(6) + 8 = -color(green)(6) + color(red)(6) + color(blue)(x_2)

2 = 0 + color(blue)(x_2)

2 = color(blue)(x_2)

color(blue)(x_2) = 2

First, find the y value of the missing coordinate:

Substituting the information from the problem gives:

2 = (color(red)(5) + color(blue)(y_2))/2

We can now solve for color(blue)(y_2):

color(green)(2) xx 2 = color(green)(2)((color(red)(5) + color(blue)(y_2))/2)

4 = cancel(color(green)(2))((color(red)(5) + color(blue)(y_2))/color(green)(cancel(color(black)(2))))

4 = color(red)(5) + color(blue)(y_2)

-color(green)(5) + 4 = -color(green)(5) + color(red)(5) + color(blue)(y_2)

-1 = 0 + color(blue)(y_2)

-1 = color(blue)(y_2)

color(blue)(y_2) = -1

The coordinates of the Midpoint are: (2, -1)