How do you find the missing coordinate if the 1st coordinate is (12, -8) and the midpoint is (3, 18)?

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How do you find the missing coordinate if the 1st coordinate is (12, -8) and the midpoint is (3, 18)?

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Answer 1 · 2018-04-13T14:16:58

$(-6,44)$

Explanation:

$"the coordinates of the midpoint are the average of the"$
$"coordinates of the endpoints"$

$"here one endpoint is "(12,-8)$

$"let the endpoint to be found "=(x,y)$

$rArr1/2(12+x)=3larrcolor(blue)"x-coordinate of midpoint"$

$"multiply both sides by 2"$

$rArr12+x=6rArrx=6-12=-6$

$rArr1/2(-8+y)=18larrcolor(blue)"y-coordinate of midpoint"$

$"multiply both sides by 2"$

$rArr-8+y=36rArry=36+8=44$

$rArr"coordinates of missing endpoint "=(-6,44)$

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How do you find the missing coordinate if the 1st coordinate is (12, -8) and the midpoint is (3, 18)?

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