How do you find the midpoint of (-3, 4) and (5, 4)?

1 Answer
Tony B
Feb 21, 2016

#color(blue)("Mid point "-> (x,y) = (1,4)". ")#Notice that as #y=4# is true for each of the given points, this is a plot of a line parallel to the x-axis. So the equation of the line is: y=4.

Explanation:

#x_("mid point") -> 1/2 #the distance between the #x# values added to the first #x# value

#y_("mid point")-> 1/2 # the distance between the #y# values added to the first #y# value.

#color(brown)("Let "(x_1,y_1) -> (-3,4))#

#color(brown)("Let "(x_2,y_2)->(5,4))#
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)("To determine "x_("mid point"))#

#x_("mid point") = x_1 + (x_2-x_1)/2" "=" "(-3)+(5-(-3))/2 #

#color(blue)(x_("mid point") " "=" "1)#

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)("To determine "y_("mid point"))#

#y_("mid point")" "=" "y_1+(y_2-y_1)/2" "=" "4+(4-4)/2#

#color(blue)(y_("mid point")" "=" "4#
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Mid point #-> (x,y) = (1,4)#

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