How do you find the midpoint of (-3, 4) and (5, 4)?

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How do you find the midpoint of (-3, 4) and (5, 4)?

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Answer 1 · 2016-02-21T21:55:23

$Mid point \to (x, y) = (1, 4) .$ $color(blue)("Mid point "-> (x,y) = (1,4)". ")$ Notice that as $y = 4$ $y=4$ is true for each of the given points, this is a plot of a line parallel to the x-axis. So the equation of the line is: y=4.

Explanation:

$x_{mid point} \to \frac{1}{2}$ $x_("mid point") -> 1/2$ the distance between the $x$ $x$ values added to the first $x$ $x$ value

$y_{mid point} \to \frac{1}{2}$ $y_("mid point")-> 1/2$ the distance between the $y$ $y$ values added to the first $y$ $y$ value.

$Let (x_{1}, y_{1}) \to (- 3, 4)$ $color(brown)("Let "(x_1,y_1) -> (-3,4))$

$Let (x_{2}, y_{2}) \to (5, 4)$ $color(brown)("Let "(x_2,y_2)->(5,4))$
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
$To determine x_{mid point}$ $color(blue)("To determine "x_("mid point"))$

$x_{mid point} = x_{1} + \frac{x_{2} - x_{1}}{2} = (- 3) + \frac{5 - (- 3)}{2}$ $x_("mid point") = x_1 + (x_2-x_1)/2" "=" "(-3)+(5-(-3))/2$

$x_{mid point} = 1$ $color(blue)(x_("mid point") " "=" "1)$

'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
$To determine y_{mid point}$ $color(blue)("To determine "y_("mid point"))$

$y_{mid point} = y_{1} + \frac{y_{2} - y_{1}}{2} = 4 + \frac{4 - 4}{2}$ $y_("mid point")" "=" "y_1+(y_2-y_1)/2" "=" "4+(4-4)/2$

$y_{mid point} = 4$ $color(blue)(y_("mid point")" "=" "4$
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
Mid point $\to (x, y) = (1, 4)$ $-> (x,y) = (1,4)$

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How do you find the midpoint of (-3, 4) and (5, 4)?

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