How do you find the midpoint of (3,1) and (7,-5)?

1 Answer
Mar 3, 2016

P_("mid") = (2,-3)

Explanation:

Let the first point be" "P_1->(x_1,y_1)->(3,1)

Let the second point be" "P_2->(x_2,y_2)->(7,-5)

Let the mid point be " "P_("mid")

The mid point between P_1" and "P_2 is such that its coordinates are the mid point of the x's and the mid point of the y's

P_("mid") ->(P_2-P_1)/2->(x,y)->( (x_2-x_1)/2,(y_2-y_1)/2)

" "= ((7-3)/2,((-5)-1)/2)

P_("mid") = (2,-3)