How do you find the midpoint of [ 11/3, 11/2] and [4/3, 3/2]?

2 Answers
Mar 12, 2016

#P_m={55/12,17/12}#

Explanation:

#P_1=[11/3,11/2]" "P_2=[4/3,3/2]#
#P_m:" Midpoint" #
#P_"m x"=(P_"1 x"+P_"2 x")/2=(11/3+11/2)/2=((22+33)/6)/2=55/12#
#P_"m y"=(P_"1 y"+P_"2 y")/2=(4/3+3/2)/2=((8+9)/6)/2=17/12#
#P_m={55/12,17/12}#

Mar 12, 2016

#(5/2,7/2)#

Explanation:

To get the #x#-coordinate of the midpoint, find the average of the #x#-coordinates.
#(11/3+4/3)/2=(15/3)/2=5/2#
To get the #y#-coordinate of the midpoint, find the average of the #y#-coordinates.
#(11/2+3/2)/2=(14/2)/2=7/2#