How do you find the midpoint of (0,4) and $(- \sqrt{2}, 0)$ $(-sqrt2,0)$ ?

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How do you find the midpoint of (0,4) and $(- \sqrt{2}, 0)$ $(-sqrt2,0)$ ?

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Answer 1 · 2018-03-24T06:42:14

$(- \frac{\sqrt{2}}{2}, 2)$ $(-sqrt(2)/2, 2)$

Explanation:

The midpoint formula tells us the midpoint between two coordinate pairs $(x_{1}, y_{1}), (x_{2}, y_{2}) = (\frac{x_{1} + x_{2}}{2}, \frac{y_{1} + y_{2}}{2})$ $(x_1,y_1), (x_2, y_2) = ((x_1+x_2)/2, (y_1+y_2)/2)$ .

Here, $x_{1} = 0, x_{2} = - \sqrt{2}, y_{1} = 4, y_{2} = 0$ $x_1=0, x_2=-sqrt(2), y_1=4, y_2=0$ , so the midpoint is

$(- \frac{\sqrt{2}}{2}, \frac{4}{2}) = (- \sqrt{\frac{2}{2}}, 2)$ $(-sqrt(2)/2, 4/2)=(-sqrt(2/2), 2)$

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How do you find the midpoint of (0,4) and $(- \sqrt{2}, 0)$ $(-sqrt2,0)$ ?

1 Answer

Explanation:

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Impact of this question

Science

Math

Humanities

... and beyond

How do you find the midpoint of (0,4) and (−√2,0)(-sqrt2,0)?

1 Answer

Explanation:

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Impact of this question

How do you find the midpoint of (0,4) and $(- \sqrt{2}, 0)$ $(-sqrt2,0)$ ?