How do you find the mean variance, and standard deviation of the binomial distribution with n= 70n=70 and p=.2p=.2?

1 Answer
Feb 19, 2018

E(X)=14E(X)=14

VAR(X)=11.2VAR(X)=11.2

sd=3.35(2dp)sd=3.35(2dp)

Explanation:

for a Binomial distribution

X~B(n,p)X~B(n,p)

mean, or expected value" "E(X)=np E(X)=np

variance " "Var(X)=np(1-p) Var(X)=np(1p)

so in this case we have

X~B(70,0.2)X~B(70,0.2)

:.E(X)=70xx0.2=14

Var(X)=70xx0.2xx0.8=11.2

sd=sqrt("Var(X)")=sqrt11.2=3.35(2dp)