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How do you find the mean, variance and standard deviation of the binomial distribution with n = 316 and p = 0.72?

1 Answer

Jan 6, 2017

The mean is #=227.52#
The variance is #=63.71#
The standard deviation is #=7.98#

Explanation:

The binomial distribution with #n=316# and #p=0.72#

The mean is #mu_x=n*p=316*0.72=227.52#

The variance is #=sigma_x^2=n*p*(1-p)=316*0.72*0.28=63.71#

The standard deviation is #=sigma_x=sqrt(n*p*(1-p))#

#=sqrt(63.7056)=7.98#

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