How do you find the mean of the following probability distribution?

Question

X P(X)
1 0.20
2 0.10
3 0.35
4 0.05
5 0.30

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Answer 1 · 2017-01-21T08:04:28

Mean is #3.15#

#[(ulx,ul(P(x))), (1, 0.20), (2, 0.10), (3, 0.35), (4, 0.05), (5, 0.30)]#

is #(sum_i xP(x))/(sum_iP(x))#

And hence mean is

#(1xx0.20+2xx0.10+3xx0.35+4xx0.05+5xx0.30)/(0.20+0.10+0.35+0.05+0.30)#

= #(0.20+0.20+1.05+0.20+1.50)/1#

= #3.15#