How do you find the maximum value of $y=x^2+2x+3$ ?

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How do you find the maximum value of $y=x^2+2x+3$ ?

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Answer 1 · 2016-09-19T17:59:13

There is no maximum value.

Explanation:

1) The graph is an upward opening parabola; there is no maximum.

2) $lim_(xrarroo)(x^2+2x+3) = oo$ , so there is no maximum.

Using $y = f(x)$ ,

3) $f'(x) = 2x+2 = 0$ at $x=-1$ . Therefore, $-1$ is the only critical number and the first or second derivative test will show that $f(-1)$ is a minimum, not a maximum.

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How do you find the maximum value of $y=x^2+2x+3$ ?

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How do you find the maximum value of y=x^2+2x+3y=x^2+2x+3?

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How do you find the maximum value of $y=x^2+2x+3$ ?