How do you find the magnitude of YZ given Y(-4,12) and Z(1,19)?

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Answer 1 · 2016-09-18T02:36:07

Use the distance formula to find $|\vec(YZ) |=sqrt(74)~~8.6$

Use the distance formula.

$d=sqrt((x_2-x_1)^2+(y_2-y_1)^2)$

$(x_1,y_1)=(-4,12)$ and $(x_2,y_2)=(1,19)$

$|\vec(YZ) |= sqrt((1- -4)^2+(19-12)^2$

$|\vec(YZ) |=sqrt(5^2+7^2)$

$|\vec(YZ) |=sqrt(25+49)$

$|\vec(YZ) |=sqrt(74)~~8.6$