How do you find the magnitude of MP given M(2,-1) and P(-3,4)? Precalculus Vectors in the Plane Direction Angles 1 Answer Ratnaker Mehta Jul 31, 2016 #5sqrt2#. Explanation: #vec(MP)#=position vector of P-position vector of M #=(-3,4)-(2,-1)# #=(-3-2,4-(-1))# #=(-5,5)# Hence, the magnitude of #vec(MP)=||vec(MP)||# #=sqrt{(-5)^2+5^2}=sqrt(25+25)=sqrt50=5sqrt2#. Answer link Related questions How do I find the direction angle of vector #<-2, -5>#? How do I find the direction angle of vector #<1, -sqrt3>#? How do I find the direction angle of vector #<-sqrt3, -1>#? How do I find the direction angle of the vector #v=10i-10j#? How do I find the magnitude and direction angle of the vector #v=3i- 4j#? How do I find the magnitude and direction angle of the vector #v =6i-6j#? Why is the direction angle important? What are some applications of the use of direction angle? How do you find the direction cosines and direction angles of the vector? How do I find the angle between the planes 5(x+1) + 3(y+2) + 2z = 0 and x + 3(y-1) + 2(z+4) = 0? See all questions in Direction Angles Impact of this question 2274 views around the world You can reuse this answer Creative Commons License