How do you find the magnitude of <2.5,6> and write it as a sum of the unit vectors?

1 Answer
Ratnaker Mehta
Sep 3, 2017

:. <2.5,6> = 2.5hati+6hatj.

||<2.5,6>||=sqrt{(2.5)^2+6^2}=sqrt(6.25+36)=sqrt(42.25)=6.5.

Explanation:

<2.5,6> = <2.5,0> + <0,6>,

=2.5<1,0> + 6<0,1>,

:. <2.5,6> = 2.5hati+6hatj.

||<2.5,6>||=sqrt{(2.5)^2+6^2}=sqrt(6.25+36)=sqrt(42.25)=6.5.

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