How do you find the magnitude <-6,-11>? Precalculus Vectors in the Plane Vector Operations 1 Answer Ratnaker Mehta Jul 13, 2016 sqrt157~=12.53 Explanation: Magnitude of a vector vecx=(x_1,x_2) is denoted by ||vecx|| & is defined by, ||vecx||=sqrt(x_1^2+x_2^2). Hence, magnitude of vector <-6,-11> is sqrt{(-6)^2+(-11)^2}=sqrt157~=12.53 Answer link Related questions Question #b4ef9 What is meant by a component of a vector? How do I find the vertical component of a vector? How do i find the horizontal component of a vector? Is vector addition commutative? What happens when I multiply a vector by itself? What is the definition of vector addition? How do I do vector subtraction? What is a velocity vector? How can the law of cosines be used to find the magnitude of a resultant? See all questions in Vector Operations Impact of this question 1905 views around the world You can reuse this answer Creative Commons License