How do you find the magnitude <2,-3>?

1 Answer
ali ergin
Aug 11, 2016

||A||=sqrt 13" "unit

Explanation:

"the magnitude of "A=<x,y> " will be " ||A||=sqrt(x^2+y^2)," if A= < x, y>"

A= <2,-3>

x=2" ; "y=-3

||A||=sqrt(2^2+(-3)^2)

||A||=sqrt(4+9)

||A||=sqrt 13" "unit

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