How do you find the local extremas for g(x) = x^2 + 1?
1 Answer
Jan 8, 2017
Explanation:
We find the critical point as solution of the equation:
As the second derivative is constant and positive this critical point is a local minimum.
The same conclusion can be drawn by direct inspection as:
(i)
g(x) is a second order polynomial so it has a single local extreme.
(ii)x^2>=0 sog(x) >=1 andg(0) = 1