How do you find the local extrema for #f(x) = 2-2x^2# on domain #-1 <= x <= 1#?

Question

How do you find the local extrema for #f(x) = 2-2x^2# on domain #-1 <= x <= 1#?

↳Redirected from "Which following pairs of atoms, have a lower electron affinity? a) Ca,K b) I,F c) Li, Ra. I seriously don't know anything about electron affinity all ik that it can buy another element"

1 Answer

Impact of this question

1673 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2016-03-10T16:17:33

It has maximum for #x=0# and value #f(0)=2# which is a absolute maximum because

#f(x)<=f(0)# for all x in #[-1,1]#

Also using derivatives we find the roots of first derivative which is

#(df(x))/dx=(d(2-2x^2))/dx=-4x#

But #(df)/dx=0=>-4x=0=>x=0#

Hence point #x=0# is a critical value of #f(x)#.Above we show that this a maximum.

The graph of #f(x)# is as follows

enter image source here

Science

Math

Humanities

... and beyond

How do you find the local extrema for #f(x) = 2-2x^2# on domain #-1 <= x <= 1#?

1 Answer

Related questions

Impact of this question