How do you find the limit of (x^2+2x-1)/(3+3x^2) as x approaches infinity?

1 Answer
May 17, 2018

1/3

Explanation:

"divide terms on numerator/denominator by "x^2

=(x^2/x^2+(2x)/x^2-1/x^2)/(3/x^2+(3x^2)/x^2)=(1+2/x-1/x^2)/(3/x^2+3)

rArrlim_(xtooo)((x^2+2x-1)/(3+3x^2))

=lim_(xtooo)((1+2/x-1/x^2)/(3/x^2+3))

=(1+0-0)/(0+3)=1/3