How do you find the limit of #sqrt(x^2+2x)+x# as x approaches infinity?

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How do you find the limit of #sqrt(x^2+2x)+x# as x approaches infinity?

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Answer 1 · 2016-11-11T22:12:31

The limit does not exist (it diverges to infinity)

Explanation:

We want # lim_(x rarr oo) sqrt(x^2+2x) + x #

Both #x^2# and #x# (and therefore #2x#) increase without bound as #x# increases, hence #sqrt(x^2+2x)# also increases without bound and the limit diverges.

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How do you find the limit of #sqrt(x^2+2x)+x# as x approaches infinity?

1 Answer

Explanation:

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