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How do you find the limit of #(sin2x)/x# as x approaches infinity?

1 Answer

Oct 1, 2016

#=0#

Explanation:

#sin 2x# is a continuous periodic function bounded as #sin 2x in [-1,1]#

therefore

#lim_(x to oo) (sin 2x)/x#

#= lim_(x to oo) c/x# with #c in [-1,1]#

#=0#

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