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How do you find the limit of #e^(-3x)# as x approaches infinity?

1 Answer

Apr 17, 2015

#e^(-3x) = 1/(e^(3x))#

As #x rarr oo#, the denominator #e^(3x) rarr oo#, so the expression:

#e^(-3x) = 1/(e^(3x)) rarr 0#

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